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Read a year and print yes if it is a leap year, otherwise no.
Divisible by 4, except centuries which must also be divisible by 400.
Input. One integer year.
Output. yes or no.
Constraints
- 1 ≤ year ≤ 9999
Examples
Input
2000
Output
yes
Input
1900
Output
no
Input
2024
Output
yes
Hint
- year % 400 == 0 is always a leap year.
- Else year % 4 == 0 && year % 100 != 0.
Show correct code
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#include <stdio.h>
int main(void) {
int year;
if (scanf("%d", &year) == 1) {
int leap = (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0);
printf(leap ? "yes\n" : "no\n");
}
return 0;
}
main.cC17 · gcc · Ctrl + Enter runs
ResultIdle
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