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The first number is n, then n integers, then a target.
Print the 0-based index of the first time the target appears, or -1 if it is missing.
Input. n, then n integers, then target — whitespace-separated.
Output. One integer: the index, or -1.
Constraints
- 1 ≤ n ≤ 100
Examples
Input
5 3 1 8 2 4 8
Output
2
Input
4 1 2 3 4 9
Output
-1
Hint
- Walk i from 0 to n-1. On a hit, print i and return.
- If the loop finishes, print -1.
Show correct code
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#include <stdio.h>
int main(void) {
int n, target;
int nums[100];
if (scanf("%d", &n) != 1 || n < 1 || n > 100) return 1;
for (int i = 0; i < n; i++) scanf("%d", &nums[i]);
scanf("%d", &target);
int found = -1;
for (int i = 0; i < n; i++) {
if (nums[i] == target) { found = i; break; }
}
printf("%d\n", found);
return 0;
}
main.cC17 · gcc · Ctrl + Enter runs
ResultIdle
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